20. Write a C program to count total number of notes in given amount.

 20. Write a C program to count total number of notes in given amount.

Solution :- 

#include<stdio.h>
#include<conio.h>
void main()
{
    clrscr();
    int amount;
    int note2000,note500,note200,note100,note50,note20,note10,note5,note2,note1;
    note2000=note500=note200=note100=note50=note20=note10=note5=note2=note1=0;
    printf("Enter the amount :-");
    scanf("%d",&amount);
    if(amount>=2000)
    {
        note2000 = amount/2000;
        amount = amount -note2000*2000;
    }
    if(amount >= 500)
    {
        note500 = amount/500;
        amount = amount - note500*500;
    }
     if(amount >= 200)
    {
        note200 = amount/200;
        amount = amount - note200*200;
    }

        if(amount >= 100)
    {
        note100 = amount/100;
        amount = amount - note100*100;
    }
         if(amount >= 50)
    {
        note50 = amount/50;
        amount = amount - note50*50;
    }

         if(amount >= 20)
    {
        note20 = amount/20;
        amount = amount - note20*20;
    }
        if(amount >= 10)
    {
        note10 = amount/10;
        amount = amount - note10*10;
    }
         if(amount >= 5)
    {
        note5 = amount/5;
        amount = amount - note5*5;
    }
         if(amount >= 2)
    {
        note2 = amount/2;
        amount = amount - note2*2;
    }
        if(amount >= 1)
    {
        note1 = amount;

    }
    else
    {
    printf("Not proper");

    }
       printf("\n2000 :- %d",note2000);
       printf("\n500 :- %d",note500);
       printf("\n200 :- %d",note200);
       printf("\n100 :- %d",note100);
       printf("\n50 :- %d",note50);
       printf("\n20 :- %d",note20);
       printf("\n10 :- %d",note10);
       printf("\n5 :- %d",note5);
       printf("\n2 :- %d",note1);
       printf("\n1 :- %d",note1);
getch();

}

Output :-